x=-1/12(x-1)^2-5

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Solution for x=-1/12(x-1)^2-5 equation: 


x in (-oo:+oo)

x = (-1/12)*(x-1)^2-5 // - (-1/12)*(x-1)^2-5

x-((-1/12)*(x-1)^2)+5 = 0

(1/12)*(x-1)^2+x+5 = 0

1/12*(x-1)^2+x+5 = 0

1/12*(x-1)^2+x+5 = 0

1/12*x^2+5/6*x+1/12+5 = 0

1/12*x^2+5/6*x+61/12 = 0

1/12*x^2+5/6*x+61/12 = 0

1/6*(1/2*x^2+5*x+61/2) = 0

1/2*x^2+5*x+61/2 = 0

DELTA = 5^2-(1/2*4*61/2)

DELTA = -36

DELTA < 0

1/6 = 0

1/6 = 0

1/6 = 0 // * 6

1 = 0

x belongs to the empty set

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